Calculations for 1 a.m.u.:
Calculated mass of Helium Nucleus
Mass of Proton 2 x 1.0078= 2.0156
Mass of Neutron 2 x 1.0087= 2.0174
4.0330
Actual mass of Helium Nucleus (-) 4.0026
Difference of the Mass 0.0304
Binding Energy of the Helium atom=
0.0304 x 931.5 = 28.3176MeV
1 a m u = 1.66 x 10 – 24 g or 1.66 x 10-27 Kg.
1
mole of a particle (proton or neutron) = 1 g.
6.023 x 10 23 particles = 1g.
E = mc2
= 1.66 x 10 – 27 Kg x (3 x 108)2 m/sec
=
1.66 x 10 – 27 x 9 x 1016
Kg-m/sec
= 14.94 x 10 – 11 J
= 1.494 x 10 – 10 J or 1.5 x 10 – 10 J
1eV. = 1.602 x 10- 19 J
Ernest Lawrence invented a device to
accelerate the electron called cyclotron.
The energy absorbed by an electron when
it accelerated towards a - ve electrode.
eV = 1.602 x 10 – 19 Coulombs
E = 1.602 x 10 – 19 e x 1 V
= 1.602 x 10 – 19‑ Coulomb – Volt (Joules)
= 1.602 x 10 – 19
1.494 x 10 – 10 J = 1 a.m.u
But, 1eV = 1.602 x 10 – 19 J
1eV = 1. 062 x 10 – 19 x 1010 amu
= 0.936 x 109 eV
=
936.3 x 106 MeV
=
936.3 MeV
The nuclear force is strong and a short-range force that acts between the particles having distance between them = 10 – 15 m or 1 fm.
N/Z (ratio between the mass of neutrons and atomic number) increases stability decreases.
e.g.: N/Z ratio for Uranium ( 92U238) is 146/92 = 1.6.
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